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If average binding energy per nucleon of X and Y is 8.5 MeV whereas that of  92236U is 7.6 MeV. Then the total energy liberated in the following reaction is

 92236U117X+117Y+n+n

a
200 keV
b
2 MeV
c
200 MeV
d
2000 MeV

detailed solution

Correct option is C

Average binding energy per nucleon of X and Y = 8.5 MeVBinding energy per nucleon of U = 7.6 MeVWhere binding energy →B.E.So total energy liberated=(B.E⋅ of X+B.E. of Y−B.E. of U=(117×8.5+117×8.5−236×7.6)=195.4≈200MeV

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In a fission reaction U 92236X  117+Y  117+n+n, the binding energy per nucleon of X and Y is 8.5 MeV where as of U  236 is 7.6 MeV. The total energy liberated will be about


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