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If $\frac{| a + b |}{| a - b |} = 1$ , then angle between a and b is

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detailed solution

Correct option is C

|a+b||a-b|=1|a+b|=|a-b|a2+b2+2abcosθ=a2+b2-2abcosθcosθ=0°θ=90°

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If |a+b||a-b|=1, then angle between a and b is

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If $\frac{| a + b |}{| a - b |} = 1$ , then angle between a and b is