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Q.

If |a+b||a-b|=1, then angle between a and b is

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a

b

45°

c

90°

d

60°

answer is C.

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Detailed Solution

|a+b||a-b|=1|a+b|=|a-b|a2+b2+2abcosθ=a2+b2-2abcosθcosθ=0°θ=90°
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