Questions
If || = ||, then the angle between will be
a
300
b
450
c
600
d
900
detailed solution
Correct option is D
Let θ be the angle between the vectors A→ and B→.Then |A→ + B→| = A2+B2+2ABcosθ|A→ − B→| = A2+B2-2ABcosθ|A→ + B→| = |A→ − B→| ∴ A2+B2+2ABcosθ = A2+B2-2ABcosθSquaring on both sides, we getA2+B2+2ABcosθ = A2+B2-2ABcosθ4ABcosθ = 0∴ cosθ = 0 or θ = π2Talk to our academic expert!
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Three forces 9 N, 12 N and 15 N acting at a point are in equilibrium the angle between 9 N and 15 N is
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