First slide

Vectors

Question

If $| \vec{A} \times \vec{B} | = | \vec{A} . \vec{B} |, then angle between \vec{A} and \vec{B} will be$

Moderate

A

$30^{0}$
B

$45^{0}$
C

$60^{0}$
D

$90^{0}$

Solution

$| \vec{A} \times \vec{B} | = \vec{A} . \vec{B} \Rightarrow ABsinθ = ABcosθ \Rightarrow tanθ = 1$
$∴ θ = 45^{0}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App