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If $| \vec{A} \times \vec{B} | = | \vec{A} . \vec{B} |, then angle between \vec{A} and \vec{B} will be$

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Correct option is B

|A→ ×B→| = A→.B→ ⇒ ABsinθ = ABcosθ ⇒ tanθ = 1 ∴ θ = 450

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If |A→×B→| = |A→.B→|, then angle between A→ and B→ will be

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If $| \vec{A} \times \vec{B} | = | \vec{A} . \vec{B} |, then angle between \vec{A} and \vec{B} will be$