If A→×B→$$=C$$→, then

Correct option is 4C→.A→+B→ must be zero

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If $\vec{A} \times \vec{B} = \vec{C}$ , then

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A→ . B→ must be zero

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C→.A→+B→ must be zero

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detailed solution

Correct option is D

Since A→×B→=C→, C→ must be perpendicular to the plane containing A→ and B→. Hence option (4) is correct. Also C→.A→ and C→.B→ must be zero.

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If A→×B→=C→, then

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If $\vec{A} \times \vec{B} = \vec{C}$ , then