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If $\vec{A}$ and $\vec{B}$ denote the sides of parallelogram and its area is $\frac{1}{2} A B$ (A and B are the magnitude of $\vec{A}$ and $\vec{B}$ respectively), the angle between $\vec{A}$ and $\vec{B}$ is

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detailed solution

Correct option is A

Area of parallelogram =|A×B| =AB sinθ=12AB ∴ sinθ=12, θ=300

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If A→ and B→ denote the sides of parallelogram and its area is 12AB (A and B are the magnitude of A→ and B→ respectively), the angle between A→ and B→ is

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Ready to Test Your Skills?

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If $\vec{A}$ and $\vec{B}$ denote the sides of parallelogram and its area is $\frac{1}{2} A B$ (A and B are the magnitude of $\vec{A}$ and $\vec{B}$ respectively), the angle between $\vec{A}$ and $\vec{B}$ is