If A→ and B→ denote the sides of parallelogram and its area is 12AB (A and B are the magnitude of A→ and B→ respectively), the angle between A→ and B→ is
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a
300
b
600
c
450
d
1200
answer is A.
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Detailed Solution
Area of parallelogram =|A×B| =AB sinθ=12AB ∴ sinθ=12, θ=300