If a ball is thrown vertically upwards with speed u, the distance covered during the last ‘t’ seconds of its ascent is :
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a
ut
b
12gt2
c
ut-12gt2
d
(u + gt)t
answer is B.
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Detailed Solution
∵ Distance covered during the last 't' seconds in ascent is equal to the distance covered during first 't' seconds in descent due to symmetry in upward and downward motion.