Q.
If a ball is thrown vertically upwards with speed u, the distance covered during the last ‘t’ seconds of its ascent is:
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a
ut
b
12gt2
c
ut−12gt2
d
u+gtt
answer is B.
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Detailed Solution
Since the motion is symmetric upwards and downwards, the distance covered in last t seconds during ascent is equal to distance covered during 1st t seconds during descent.Hence, Displacement in last t seconds during ascent= 12gt2
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