Questions
If a ball is thrown vertically upwards with speed
a
ut
b
12gt2
c
ut−12gt2
d
(u+gt)t
detailed solution
Correct option is B
Let T be the time of ascent and H be the total height. Then T=u/g And H=uT−12gT2 Let (T−t) be the time taken by the ball to travel part of H. The distance covered in(T- t )sec is x=u(T−t)−12g(T−t)2So distance covered by ball in last t secondsh=H−x=[uT−12gT2]−[u(T−t)−12g(T−t)2] =ut−gtT+12gt2=12gt2[∵T=u/g]Talk to our academic expert!
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An object is vertically thrown upwards. Then the displacement-time graph for the motion is as shown in
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