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If the banking angle of curved road is given by $\tan^{- 1} (\frac{3}{5})$ and the radius of curvature of the road is
6 m, then the safe driving speed should not exceed (Take, g = 10 ms^-2)

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86.4 km h-1

43.2 km h-1

21.6 km h-1

30.4 km h-1

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detailed solution

Correct option is C

tanθ=v2gr⇒35=v210×6⇒ v=6 ms-1=21.6kmh-1

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If the banking angle of curved road is given by tan-135 and the radius of curvature of the road is6 m, then the safe driving speed should not exceed (Take, g = 10 ms-2)

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If the banking angle of curved road is given by $\tan^{- 1} (\frac{3}{5})$ and the radius of curvature of the road is
6 m, then the safe driving speed should not exceed (Take, g = 10 ms^-2)