First slide

Elastic Modulie

Question

If a bar is made of · copper whose coefficient of linear expansion is one and a half times that of iron, the ratio of force developed in the copper bar to the iron bar of identical lengths and cross-sections, when heated through the same temperature range (Young's modulus of copper may be taken to be equal to that of iron) is:

Moderate

A

3/2
B

2/9
C

9/4
D

4/9

Solution

$Thermal tension = YAα ∆ θ \Rightarrow T \infty α \Rightarrow \frac{T_{Cu}}{T_{iron}} = \frac{α_{Cu}}{α_{iron}} = \frac{3}{2}$

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