If a bar magnet of magnetic moment M is freely suspended in a uniform magnetic field of strength B, the work done in rotating the magnet through an angle θ is
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a
MB(1−sinθ)
b
MB sinθ
c
MB cosθ
d
MB(1−cosθ)
answer is D.
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Detailed Solution
W = M B (1-COS θ) W is the work done in rotating the bar magnet through an angle θ from the field direction.