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Q.

If the binding energies of  12H,13 H and 24He are, respectively, a, b and c, then find the energy released in the following reaction : 12H+13H→24He+01n

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a

c+a−b

b

c−a−b

c

a+b+c

d

a+b−c

answer is B.

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Detailed Solution

Energy Q released is equal to total energy of product side minus total energy of reactant.Q=c−(a+b)Q=c−a−b
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