If binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 MeV, respectively then find the energy of the following reaction :Li7+p( proton )→2He4

The binding energy for proton  H11 is around zoro and also not given in the question. So we can ignore it.Binding energy = (Total energy of product side) -(Total energy of reactant side)Binding energy per nucleon B⋅EA in L7 is 5.60 MeVTotal binding energy of (L7)=7×5.60 MevBinding energy per nucleon B⋅EA in He4 is 7.60 MeVTotal binding energy of (He4)=4×7.06 Mev Total energyQ=2(4×7.06)−(7×5.60)=56.48−39.2=17.28≈17.3 MeV