If a body is executing simple harmonic motion and its current displacement is 3/2 times the amplitude from its mean position, then the ratio between potential energy and kinetic energy is

The current displacement is 32times the amplitude,i.e.         y=32AWe know that, potential energy of 11 body in SHM is given by              U=12mω2y2where, m and ω are constants.            U=12mω232A2=12mω2×3A24                      …(i)Similarly, kinetic energy of a body it SHM is given by            K=12mω2A2-y2               =12mω2A2-3A24=12mω2A24                       …(ii)So, the ratio of PE and KE,       PE : KE=12mω2×3A24 : 12mω2A24=3 : 1