If the body is projected vertically up with a velocity V, then the velocity of the body at half of the maximum height H is,$$($$ acceleration due to $$gravity=g)$$

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Infinity Learn · Accepted Answer

by question ,velocity of projection $$=u=V$$; acceleration due to $$gravity=a=g$$; final $$velocity=V=0$$; $$displacement=maximum$$ height⇒$$s=H$$  we know, $$V2=U2+2aS$$ $$0=V2+2(-g)H$$ $$H=V22g---(1)$$ to find, $$velocity=V=vmid$$ point at $$s=H2$$;velocity of projection $$=u=V$$ substitute in $$V2=U2+2aS$$ $$v2mid$$ $$point=V2+2(-g)(H2)$$ substitute equation (1) $$v2mid$$ $$point=V2-gV22g$$ $$v2mid$$ $$point=V2-V22$$ $$v2mid$$ $$point=V22$$ square root both sides vmid $$point=V2$$

If the body is projected vertically up with a velocity V, then the velocity of the body at half of the maximum height H is,( acceleration due to gravity=g)

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