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Q.

If a bullet of mass 5 gm moving with velocity 100 m/sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is

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a

8300 N

b

417 N

c

830 N

d

zero

answer is B.

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Detailed Solution

u = 100 m/s, v = 0, s = 0.06 mRetardation = a = u22s= (100)22×0.06 = 1 × 10612Force = ma = 5×1×10-3×10612 = 500012 = 417 N
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