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If $γ = \frac{C_{P}}{C_{V}}, C_{P}$ being the molar specific heat of a gas at constant pressure and $C_{V}$ its molar specific heat at constant volume, number of degrees of freedom of a molecule of gas can be expressed as:

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52(γ-1)

7γ-13γ-1

32γ-1

2γ-1

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detailed solution

Correct option is D

γ=1+2f⇒f=2γ-1

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If γ=CPCV,CP being the molar specific heat of a gas at constant pressure and CV its molar specific heat at constant volume, number of degrees of freedom of a molecule of gas can be expressed as:

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If $γ = \frac{C_{P}}{C_{V}}, C_{P}$ being the molar specific heat of a gas at constant pressure and $C_{V}$ its molar specific heat at constant volume, number of degrees of freedom of a molecule of gas can be expressed as: