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Q.

If the cathode-anode potential difference in an X-ray tube be 105 V, then the maximum energy of X-ray photon can be

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a

105 J

b

105 MeV

c

10-1 MeV

d

105 KeV

answer is C.

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Detailed Solution

since  λmin=12375VAo=12375105Ao=0.123 AoEmax=hcλmin;On  putting  the  values.  Emax≅10−1MeV.
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