If a charged particle of charge to mass ratio α enters in a magnetic field of strength B at a speed v=2αd B, then
angle subtended by the path of charge particle in magnetic field at the centre of circular path is 2π.
the charge will move on a circular path and then will come out from magnetic field at some distance from the point of insertion
the time for which particle will be in the magnetic field is 2παB
angle subtended by the path of charge particle in magnetic field at the centre of circular path is π/2
r=mvqB = vBα = 2αd BBα = 2d
i.e., the electron will move out after travelling on a semicircular path of radius r = 2d.