Questions
If a charged particle of charge to mass ratio enters in a magnetic field of strength B at a speed , then
a
angle subtended by the path of charged particle in magnetic field at the center of circular path is 2π
b
the charge will move on a circular path and then will come out from magnetic field at some distance from the point of insertion
c
the time for which particle will be in the magnetic field is 2παB
d
angle subtended by the path of charged particle in magnetic field at the center of circular path is π/2
detailed solution
Correct option is B
r=mvqB=vBα=(2αd)(B)(Bα)=2di.e., the electron will move out after travelling on a semicircular path of radius r = 2d.Talk to our academic expert!
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