Questions
If 1 of water is vaporized (latent heat of vaporization = 540 ) at P = 1 atm. If the volume of steam formed is 1671 , calculate increase in internal energy.
detailed solution
Correct option is D
∆Q = ∆U + ∆Wm = 1 gmLv = 540 cal/gm∆Q = 1×540 = 540540 = ∆U + P∆V540 = ∆U + 105×(1671-1)×10-6540 = ∆U + 167∆U = 540-167 = 373 calTalk to our academic expert!
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