First slide

Variation of friction with applied force

Question

If the coefficient friction between A and B is $μ$ , the maximum acceleration of the wedge A for which B will remain at rest with respect to the wedge is

Difficult

A

$μg$
B

$g (\frac{1 + μ}{1 - μ})$
C

$g (\frac{1 - μ}{1 + μ})$
D

$\frac{g}{μ}$

Solution

For maximum acceleration body as a tendency to go up and friction acting down the plane.
$macosθ = mgsinθ + f$
$macosθ = mgsinθ + μ (masinθ + mgcosθ)$
$a = g + μ (a + g) (θ = 45^{o})$
$a = g (\frac{1 + μ}{1 - μ})$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App