First slide

Pontial due to

Question

If on the concentric hollow spheres of radii r and R (> r) the charge Q is distributed such that their surface densities are same then the potential at their common centre is:

Easy

A

$\frac{Q (R^{2} + r^{2})}{4 {πε}_{0} (R + r)}$
B

$\frac{QR}{R + r}$
C

Zero
D

$\frac{Q (R + r)}{4 {πε}_{0} (R^{2} + r^{2})}$

Solution

$q_{1} + q_{2} = Q and \frac{q_{1}}{4 {πr}^{2}} = \frac{q_{2}}{4 {πR}^{2}} q_{1} = \frac{{Qr}^{2}}{R^{2} + r^{2}} and q_{2} = \frac{{QR}^{2}}{R^{2} + r^{2}} Potential at common centre \frac{1}{4 {πε}_{0}} [\frac{{Qr}^{2}}{(R^{2} + r^{2}) r} + \frac{{QR}^{2}}{(R^{2} + r^{2}) R}] = \frac{Q (R + r)}{4 {πε}_{0} (R^{2} + r^{2})}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App