If a conductor of 3 m in length is moving perpendicularly to magnetic field of 10-3 tesla with the speed of 102 m/s, then the e.m.f. produced across the ends of conductor will be

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0.03 volt

0.3 volt

3×10-3 volt

3 volt

answer is B.

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Detailed Solution

e=lBv=3×10-3×102 volt=0.3 volt

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