First slide

Torque

Question

If a constant torque of 5OO N-m turns a wheel of moment of inertia 1OO kg-m² about an axis passing though its centre, then the gain in angular velocity in 2 sec. is

Moderate

A

10 rad/sec
B

5 rad,/sec
C

2 .5 rad,/sec
D

10 rad,/sec2

Solution

$τ = Iα, where I =$ moment of inertia of wheel about an axis passing through its centre
But $α = dω / dt, hence τ = I (dω / dt)$
5u6s1i1uting the values, we get
$500 = 100 \frac{dω}{2} or dω = 10 rad / \sec$

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