If a current I given by  ${\mathrm{I}}_0\sin \mathrm{\hspace{0.17em}}\left(\mathrm{\omega }\mathrm{\hspace{0.17em}}\mathrm{t}-\frac{\mathrm{\pi }}{2}\right)$  flows in an ac circuit across which an ac potential of  $\mathrm{E}={\mathrm{E}}_0\mathrm{sin\omega }\mathrm{t}$ has been applied, then the power consumption P in the circuit will be

• A

  $\mathrm{P}=\frac{{\mathrm{E}}_0{\mathrm{I}}_0}{\sqrt{2}}$

• B

  $\mathrm{P}=\sqrt{2}{\mathrm{E}}_0{\mathrm{I}}_0$

• C

  $\mathrm{P}=\frac{{\mathrm{E}}_0{\mathrm{I}}_0}{2}$

• D

  P = 0