If a current $\mathrm{I} = {\mathrm{I}}_0\sin \left(\mathrm{\omega t}-\frac{\mathrm{\pi }}{2}\right)$ flows in an AC circuit across which an AC potential of $\mathrm{E}={\mathrm{E}}_0\sin \mathrm{\omega t}$ has been applied, then the power consumption P in the circuit will be

• A

  $\mathrm{P}=\frac{{\mathrm{E}}_0{\mathrm{I}}_0}{\sqrt{2}}$

• B

  $\mathrm{P}=\sqrt{2}{\mathrm{E}}_0{\mathrm{I}}_0$

• C

  $\mathrm{P}=\frac{{\mathrm{E}}_0{\mathrm{I}}_0}{2}$

• D

  P = 0