If a current of $$5$$ A is passed through a straight wire of length $$6$$ cm, then the magnetic induction at a point $$5$$ cm from the either end of the wire is

Question

Infinity Learn · Accepted Answer

Let AB represents the current carrying conductor and P the point where magnetic induction B is required.Now,    $$B=$$μ$$0I4$$π  $$sin$$ ϕ$$1$$ $$+$$ $$sin$$ ϕ$$2$$ Here,  $$r=OPNow$$,  $$AO=OB=62$$  cm $$=$$ $$3$$ cmAnd   $$PB=PA=5$$  $$cmOP=$$ $$PB2$$ − $$OB2=$$  $$52$$ −$$32$$ $$=$$ $$4$$  $$cmr=4$$  cm  $$=$$ $$4$$  × $$10$$−$$2$$  metresin ϕ$$1$$ $$=35$$  and  $$sin$$ ϕ$$2$$ $$=$$ $$35B=10$$−$$7$$  $$54$$ ×  $$10$$−$$2$$  $$35$$ $$+$$ $$35=$$ $$64$$  ×  $$10$$−$$5$$ $$=$$ $$0.15$$  ×  $$10$$−$$4$$ $$tesla=0.15$$  gaussThe direction of magnetic induction is normal to the plane of ABP.

If a current of 5 A is passed through a straight wire of length 6 cm, then the magnetic induction at a point 5 cm from the either end of the wire is

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