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Q.

If the d.c. voltage applied across a bulb increases by 2% and the resistance of its filament increases by 1% what is the maximum change in power dissipated in the bulb?

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a

3%

b

5%

c

7%

d

9%

answer is B.

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Detailed Solution

P=V2R⇒(ΔPP)max⁡×100%=2(ΔVV)×100%+(ΔRR)×100%∴ (ΔPP)max⁡×100%=2×2%+1%=5%
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