Questions
If the d.c. voltage applied across a bulb increases by 2% and the resistance of its filament increases by 1% what is the maximum change in power dissipated in the bulb?
detailed solution
Correct option is B
P=V2R⇒(ΔPP)max×100%=2(ΔVV)×100%+(ΔRR)×100%∴ (ΔPP)max×100%=2×2%+1%=5%Talk to our academic expert!
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A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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