If de Broglie wavelength of an electron and a position are same, then which quantity / quantities will be the same for both?
Accelerating potential
kinetic energy
Linear momentum
All of the above are correct
λ=hp⇒p=hλ
Again, p22m=E⇒E=h22mλ2
Also, kinetic energy E = eV
Hence option - (4) is right.