If A denotes the area of free surface of a liquid and} the depth of an orifice of area of cross-section o below the liquid surface then the velocity r of flow through the orifice is given by
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a
v=(2gh)
b
V=(2gh)A2/A2−a2
c
V=(2gh){A/(A−a)}
d
v=(2gh)A2−a2/A2
answer is B.
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Detailed Solution
Applying Bernoulli's theorem, the rate off low from surface to orifice is given byP+12ρv′2+ρgh=P+12ρv2+0 where v' = velocity of all surfacses of liquid. If v is velocity of efflux, then Av′=av or v′=(av/A) From eqs. (1) and (2), we 8et 12ρavA2+ρgh=12ρv2 or v2−a2v2A2=2gh V=2ghA2A2−a21/2