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If $A$ denotes the area of free surface of a liquid and $h$ the depth of an orifice of area of cross-section $a$ , below the liquid surface, then the velocity $v$ of flow through the orifice is given by :

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v=2gh

v=2gh(A2A2−a2)

v=2gh(AA−a)

v=2gh(A2−a2A2)

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detailed solution

Correct option is B

Applying Bernoulli’s theorem, we have Pρ+12(v')2+gh=Pρ+12v2+0 Where v' is the velocity of all surfaces of liquid and v the velocity of efflux.Further, from continuity equation,Av'=av or v'=avA ∴ 12(avA)2+gh=12v2 ∴ v=2gh(A2A2−a2)

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If A denotes the area of free surface of a liquid and h the depth of an orifice of area of cross-section a , below the liquid surface, then the velocity v of flow through the orifice is given by :

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If $A$ denotes the area of free surface of a liquid and $h$ the depth of an orifice of area of cross-section $a$ , below the liquid surface, then the velocity $v$ of flow through the orifice is given by :