If A denotes the area of free surface of a liquid and h the depth of an orifice of area of cross-section a , below the liquid surface, then the velocity v of flow through the orifice is given by :
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a
v=2gh
b
v=2gh(A2A2−a2)
c
v=2gh(AA−a)
d
v=2gh(A2−a2A2)
answer is B.
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Detailed Solution
Applying Bernoulli’s theorem, we have Pρ+12(v')2+gh=Pρ+12v2+0 Where v' is the velocity of all surfaces of liquid and v the velocity of efflux.Further, from continuity equation,Av'=av or v'=avA ∴ 12(avA)2+gh=12v2 ∴ v=2gh(A2A2−a2)