If the density of material of a square plate and a circular plate shown in is same, the centre of mass of the composite system will be
Inside the square plate
Inside the circular plate
At the point of contact
Outside the system
Mass of square plate M1 = l2σ
Mass of circular disc M2 = (πl24)σ
αcm = M1×0+πl2σl4l2σ[1+π4] ⇒ xcm = πl4(π+4)4 = πlπ+4
xcm<l2, i.e., C.O.M. lies in the square