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Q.

If the density of a small planet is the same as that of earth, while the radius of the planet is 0.2 times that of the earth, the gravitational acceleration on the surface of that planet is

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a

0.2 g

b

0.4 g

c

2 g

d

4 g

answer is A.

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Detailed Solution

g=43πGRρ and g′=43πGR′ρ∴g′g=R′R=0.2⇒g′=0.2g
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