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If the dimensions of a physical quantity are given by MaLbTc, then the physical quantity will be

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By Expert Faculty of Sri Chaitanya
a
velocity if a = 1, b = 0, c = – 1
b
acceleration if a = 1, b = 1, c = – 2
c
force if a = 0, b = – 1, c = – 2
d
pressure if a = 1, b = –1, c = –2
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detailed solution

Correct option is D

Pressure, P= force  area = mass × acceleration  area ∴[P]=M1LT−2L2=M1L−1T−2=MaLbTc.∴ a=1,b=−1,c=−2.


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