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Q.

If the dimensions of a physical quantity are given by MaLbTc, then the physical quantity will be

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a

velocity if a = 1, b = 0, c = – 1

b

acceleration if a = 1, b = 1, c = – 2

c

force if a = 0, b = – 1, c = – 2

d

pressure if a = 1, b = –1, c = –2

answer is D.

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Detailed Solution

Pressure, P= force  area = mass × acceleration  area ∴[P]=M1LT−2L2=M1L−1T−2=MaLbTc.∴ a=1,b=−1,c=−2.
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