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If a disc starting from rest acquires an angular velocity of 240 rev min-1 in 10s, then its angular acceleration will be [BCECE (Mains) 2012]
(a)4.26 rad/s-2  (b) 3.11 rad s-2
(c) 2.51 rad s-2 (d) 1.13 rad S-2

a
1.52 rad s-1
b
3.11 rad s-1
c
2.51 rad s-1
d
1.13 rad s-1

detailed solution

Correct option is C

Here,  ω2=2πn2=2×24060 and ω1=2πn1=0The angular acceleration,  α=ω2−ω1t∴    α=2π24060−010=2.51rads−2

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