If a disc starting from rest acquires an angular velocity of 240 rev min-1 in 10s, then its angular acceleration will be [BCECE (Mains) 2012](a)4.26 rad/s-2 (b) 3.11 rad s-2(c) 2.51 rad s-2 (d) 1.13 rad S-2
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a
1.52 rad s-1
b
3.11 rad s-1
c
2.51 rad s-1
d
1.13 rad s-1
answer is C.
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Detailed Solution
Here, ω2=2πn2=2×24060 and ω1=2πn1=0The angular acceleration, α=ω2−ω1t∴ α=2π24060−010=2.51rads−2