If the displacement x and velocity (v) of a particle executing simple harmonic motion are related through the expression 9v2=36−x2, here x is in meter and V is in m/s. Then time period of vibration is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

4.5 π sec

8π3sec

4π sec

6π sec

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

9V2=36−x2⇒V=1362−x2Comparing this equation with the standard equation V=ωA2−x2, we can write ω=13rad/s∴ T=2π/ω=2π1/3sec=6π sec

Watch 3-min video & get full concept clarity