First slide

Location of centre on mass for multiple point masses

Question

If the distance between the centres of the atoms of potassium and bromine in KBr molecule is 0.282 × 10^-9 m, the distance of centre of mass of this two particle system from potassium is (mass of bromine = 80 u and of potassium = 39 u).

Easy

A

9.3 × 10^-2 nm
B

18.96 × 10^-2 nm
C

27.9 × 10^-2 nm
D

3.3 × 10^-2 nm

Solution

distance of CM from m₁ is
$\large \frac{{{m_2}d}}{{{m_1} + {m_2}}} = \frac{{80 \times 0.282 \times {{10}^{ - 9}}}}{{39 + 80}}$
$\large = 0.1896 \times {10^{ - 9}}m = 18.96 \times {10^{ - 2}}nm$

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