If the distance travelled in nth sec is $s_n=2+0.6n$ . Find its initial velocity (in m/s)

From equation  $s_n=u+a\left(n-\frac{1}{2}\right)$
Where u= initial velocity 
 a= uniform acceleration 
 $\Rightarrow s_n=\left(u-\frac{a}{2}\right)+an\mathrm{....}\left(i\right)$
Given that  
$s_n=2+0.6n\mathrm{.......}\left(ii\right)$ 
Comparing  (i) & (ii)
$\begin{array}{l}\left(u-\frac{a}{2}\right)=2\\ a=0.6\mathrm{m}/{\mathrm{s}}^2\\ u=2+\frac{a}{2}\\ =2+\frac{0.6}{2}\\ =2+0.3=2.3\mathrm{m}/\mathrm{s}\end{array}$