If the distance travelled in nth sec is sn=2+0.6 n . Find its initial velocity (in m/s)

From equation  sn=u+an−12Where u= initial velocity  a= uniform acceleration  ⇒sn=u−a2+an....(i)Given that  sn=2+0.6n.......(ii) Comparing  (i) & (ii)u−a2=2a=0.6m/s2u=2+a2=2+0.62=2+0.3 =2.3m/s