First slide

Electrostatic potential energy

Question

If E is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

Easy

A

E
B

E²
C

1 / E²
D

E³

Solution

Electrostatic energy density $\frac{dU}{dV} = \frac{1}{2} {Kε}_{0} E^{2}$
$∴ \frac{dU}{dV} \propto E^{2}$

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