First slide

Gravitational field intensity

Question

If the earth shrinks to half of its radius and mass remains constant, then the weight of an object on earth will become

Easy

A

doubled
B

halved
C

fourtimes
D

same

Solution

On the surface of earth
$\large g = \frac{GM_e}{R^2}\\\\ \therefore W =mg=\frac{GM_em}{R^2}$
When the radius is reduced to R/2
$\fn_cm \large W'=mg'=m\;X\;\frac{GM_e}{(R/2)^2}\\\\ \therefore \frac{W'}{W}=4$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App