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Q.

If electric field is given by E→=100x2 i^, the potential difference between points x = l 0 and x = 20 is :

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a

1

b

2

c

5

d

10

answer is C.

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Detailed Solution

∆V=∫-E→.dr→=-∫100x2i^.dx i^+dx j^+dx k^                             =∫1020100x2dx                            =100x1020=10020-10010=-5 volt
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If electric field is given by E→=100x2 i^, the potential difference between points x = l 0 and x = 20 is :