First slide

electric current

Question

If $62.5 \times 10^{18}$ electrons per second are,flowing through a wire of area of cross-section $0.1 m^{2}$ the value of current flowing will be

Easy

A

1 A
B

0.1 A
C

10 A
D

0.11 A

Solution

$i = \frac{n e}{t} = \frac{62.5 \times 10^{18} \times 1.6 \times 10^{- 19}}{1} = 10 a m p e r e s$

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