If 62.5 × 1018 electrons per second are,flowing through a wire of area of cross-section 0.1 m2 the value of current flowing will be

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1 A

0.1 A

10 A

0.11 A

answer is C.

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Detailed Solution

i=net = 62.5 × 1018 × 1.6 × 10−19 1 =10 amperes

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