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Q.

If 62.5  ×  1018 electrons per second are,flowing through a wire of area of cross-section 0.1  m2 the value of current flowing will be

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a

1 A

b

0.1 A

c

10 A

d

0.11 A

answer is C.

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Detailed Solution

i=net = 62.5 × 1018 ×  1.6 × 10−19 1 =10  amperes
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If 62.5  ×  1018 electrons per second are,flowing through a wire of area of cross-section 0.1  m2 the value of current flowing will be