Download the app

Questions  

If 62.5  ×  1018 electrons per second are,flowing through a wire of area of cross-section 0.1  m2 the value of current flowing will be

a
1 A
b
0.1 A
c
10 A
d
0.11 A

detailed solution

Correct option is C

i=net = 62.5 × 1018 ×  1.6 × 10−19 1 =10  amperes

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If E denotes electric field in a uniform conductor, i corresponding current through it and v7 drift velocity of electrons, then which of the following graphs is correct 


phone icon
whats app icon