First slide

Pseudo force

Question

If an elevator is moving vertically upwards with an acceleration a, the force exerted on the floor by a passenger of mass M is

Moderate

A

Ma
B

Mg
C

M(g-a)
D

M(g+a)

Solution

Since the direction of acceleration of the lift is vertically upward , pseudo force acting on the passenger is vertically downward.
.: N = Mg+Ma = M (g+a)

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