First slide

Dimensions of physical quantities

Question

If energy E, length L and, time T are taken as fundamental quantities. The dimensional formula of gravitational constant is

Moderate

A

$[F L^{6} E^{- 2}]$
B

$[F L^{5} T^{- 1}]$
C

$[E^{2} F L^{6} T^{3}]$
D

$[E^{3} F^{- 1} L^{6} T^{5}$

Solution

$\begin{array}{l} ∴ [E] = [M L^{2} T^{- 2}] \\ [M] = [E L^{- 2} T^{2}] \\ ∵ F = \frac{G m_{1} m_{2}}{r_{2}} \\ \Rightarrow [G] = \frac{F r^{2}}{m_{1} m_{2}} = [F L^{2} M^{- 2}] \\ [F L^{2}] {[E L^{- 2} T^{- 2}]}^{- 2} = [F L^{6} E^{- 2}] \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App