Questions

If energy E, length L, and time T are taken as fundamental quantities. The dimensional formula of gravitational constant is

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FL6E−2

FL5T−1

E2FL6T3

E3F−1L6T6

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detailed solution

Correct option is

∴ E = ML2T−2⇒ M = EL−2T2∴ F = Gm1m2r2⇒ G = Fr2m1m2 = FL2M−2FL2EL−2T−2−2 = FL6E−2

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