Questions
If the energy of a photon corresponding to a wavelength of 6000 is the photon energy for a wavelength of 4000 will be
detailed solution
Correct option is C
E=hcλ⇒E1E2=λ2λ1⇒3.32×10−19E2=40006000E2=4.98×10−19J=3.1 eVTalk to our academic expert!
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