If equation of displacement of a particle is = A sin PT + B cos PT then motion of particle is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Simple harmonic motion
b
Linear motion
c
Uniform circular motion
d
Uniform elliptical motion
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
y = A sin PT + B cos PTDifferentiate w.r.t. to T, dydT = PA cos PT – PB sin PTAgain differentiate w.r.t. to T, d2ydT2= – P2A sin PT – BP2 cos PT= – P2 [A sin PT + B cos PT] ⇒+ P2y = 0 This is equation for S.H.M