If equation ∫dt3at-2t2  = axsin-1(t2a2-1), the value of  x is

(t2a2-1) is dimensionless∴[a] = [t]As, (3at-2t2) = [t]∴ [dt3at-t2]= [t][t]= [M0L0T0]ax should be dimensionless, so x = 0.