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Questions  

If equation dt3at-2t2  = axsin-1(t2a2-1), the value of  x is

a
32
b
0
c
12
d
-12

detailed solution

Correct option is

(t2a2-1) is dimensionless∴[a] = [t]As, (3at-2t2) = [t]∴ [dt3at-t2]= [t][t]= [M0L0T0]ax should be dimensionless, so x = 0.

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dt2at-t2  = axsin-1[ta-1]   The value of x is


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