If equation ∫dt3at-2t2 = axsin-1(t2a2-1), the value of x is
32
0
12
-12
(t2a2-1) is dimensionless
∴[a] = [t]
As, (3at-2t2) = [t]
∴ [dt3at-t2]= [t][t]= [M0L0T0]
ax should be dimensionless, so x = 0.